cos4x=1-8sin^2xcos^2x...

`cos4x=1-8sin^2xcos^2x`

Answer

Step by step text solution for cos4x=1-8sin^2xcos^2x by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Desktop Dark

Doubtnut Promotions Banner Mobile Dark

|

Similar Questions

Explore conceptually related problems

Prove that cos4x=1-8sin^(2)xcos^(2)x

Prove the following cos4x=1-8"sin"^(2)xcos^(2)x

Knowledge Check

int(sin^8x-cos^8x)/(1-2sin^2xcos^2x)dx is equal to

A

`sin2X+C`

B

`-1/2sin2x+C`

C

`1/2sin2x+C`

D

`-sin2x+C`

Similar Questions

Explore conceptually related problems

Prove that :cos4x=1-8sin^(2)x cos^(2)x

cos4x=1-8sin^(2)x cos^(2)x

cos4x=1-8sin^(2)x cos^(2) x

What is intfrac[sin^8x-cos^8x][1-2sin^2xcos^2x]dx ?

Prove that sin^4x + cos^4x = 1 - 2sin^2xcos^2x

int(sin^8x-cos^8x)/(1-2sin^2xcos^2x)dx=

int(sin^8x-cos^8x)/(1-2sin^2xcos^2x)dx=

Recommended Questions

cos4x=1-8sin^2xcos^2x
01:59
|
cos4x=1-8sin^(2)x cos^(2)x
01:59
|
cos4x=1-8sin^(2)x cos^(2)x
01:59
|
Prove that :cos 4x = 1 - 8 sin^2 x cos^2 x.
01:51
|
1+ cos 2x+ cos4x + cos 6x=
03:56
|
cos4x=1-8sin^(2)x cos^(2) x
01:38
|
inte^(2x) ((sin4x-2)/(1-cos4x)) का मान है
02:48
|
Integrate the functions(sin^8x-cos^8x)/(1-2sin^2xcos^2x)
03:10
|
Evaluate: intsin^2xcos^2x dx
02:40
|