Write the distance between the vertex and focus of the parabola `y^2+6y+2x+5=0.`

The distance between the vertex and the focus of the parabola x^2-2x+3y-2=0 is

The distance between the vertex and the focus of the parabola x^(2) - 2x + 3y - 2 = 0 is

The distance between the vertex and the focus of the parabola x ^(2) -2x + 3y-2 =0 is

The distance between the vertex and the focus of the parabola x^(2)-2x+3y-2=0 is

Find the vertex and focus of the given parabola x^(2)+4y=0

The vertex and focus of parabola (y-2)^(2) = -4(x-4) are

The vertex and focus of parabola (y-2)^(2) = -4(x-4) are

If V and S are respectively the vertex and focus of the parabola y^(2)+6y+2x+5=0 then SV= a.2 b.1/2c.1d .none of these

If V and S are respectively the vertex and focus of the parabola y^2+6y+2x+5=0, then S V= a. 2 b. 1/2 c. 1 d. none of these