[" The equation of the circle with "(x_(1),y_(1))" and "],[(x_(2),y_(2))" as the extremities of a diameters is "]

A: The equation of the circle (2,-3), (-3,2) as ends of a diameter is x^(2)+y^(2)+x+y-12=0 R: The equation of the circle having the line segment joining A(x_(1),y_(1)) and B(x_(2),y_(2)) as diameter (x-x_(1)) (x-x_(2))+(y-y_(1)) (y-y_(2))=0

" The equation of director circle of "(x-x_(1))^(2)+(y-y_(1))^(2)=r^(2)" is "

Show that equations of a circle with end points of diameter (x_(1),y_(1))and(x_(2),y_(2)) is same as the equation of circle with end points of diameter (x_(1),y_(2))and(x_(2),y_(1)) . Give reason.

The equation of a circle whose end the points of a diameter are (x_(1), y_(1)) and (x_(2),y_(2)) is

The equation of director circle of (x-x_(1))^(2)+(y-y_(1))^(2)=r^(2) is

The equation of the circle drawn with the two foci of x^2/a^2+y^2/b^2=1 as the end-points of a diameter is

If the end points of a diameter of circle are A(x_(1),y_(1)) and B(x_(2),y_(2)) then show that equation of circle will be (x-x_(1))(x-x_(2))+(y-y_(1))(y-y_(2))=0

If the end points of a diameter of circle are A(x_(1),y_(1)) and B(x_(2),y_(2)) then show that equation of circle will be (x-x_(1))(x-x_(2))+(y-y_(1))(y-y_(2))=0