If `sin3A=cos(A-26^@)`, where 3A is an acute angle, find the value of A.

Explanation

To solve the equation \( \sin 3A = \cos(A - 26^\circ) \), where \( 3A \) is an acute angle, we can follow these steps:

### Step 1: Use the co-function identity
We know that \( \sin \theta = \cos(90^\circ - \theta) \). Therefore, we can rewrite the left side of the equation:
\[ \sin 3A = \cos(90^\circ - 3A) \]
Now, we have:
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