[(1)/(x)+(1)/(y)=7],[(2)/(x)+(3)/(y)=17(x!=0,y!=0)]

( 1 ) /(x) + (1 ) /( y) = 7 , ( 2)/(x) + ( 3) /( y) = 17 (x ne 0, y ne 0 ) .

Solve for x and y : (1)/( 7x ) + ( 1) /( 6y) = 3, (1)/( 2x) - (1)/( 3y ) = 5 (x ne 0, y ne 0)

Solve for x and y:(xy)/(x+y)=(1)/(5),x+y!=0;(xy)/(x-y)=(1)/(7),x-y!=0

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

If the points (x_(1),y_(1)),(x_(2),y_(2)), and (x_(3),y_(3)) are collinear show that (y_(2)-y_(3))/(x_(2)x_(3))+(y_(3)-y_(1))/(x_(3)x_(1))+(y_(1)-y_(2))/(x_(1)x_(2))=0

If (x+y)/(0.01)=7 , then (1)/(2x+2y)=

Find the values of x and y from each of the following matrix equation : (i) [{:(x+y),(x-y):}]=[(3)/(1)](ii) [{:(x+y,7),(0,2x):}]=[{:(-1,7),(0,6):}]

Find the values of x and y from each of the following matrix equation : (i) [{:(x+y),(x-y):}]=[(3)/(1)](ii) [{:(x+y,7),(0,2x):}]=[{:(-1,7),(0,6):}]

If {:2[(3,4),(5,x)] + [(1,y ),(0,1)] = [(7,0),(10,5)] , find (x-y).