Home
Class 11
MATHS
Let there be ngeq3 circles in a plane. T...

Let there be `ngeq3` circles in a plane. The value of `n` for which the number of radical centers is equal to the number of radical axes is (assume that all radical axes and radical centers exist and are different). a. `7` b. `6` c. `5` d. none of these

Promotional Banner

Similar Questions

Explore conceptually related problems

Let there be n>=3 circles in a plane.The value of n for which the number of radical centers is equal to the number of radical axes is (assume that all radical axes and radical centers exist and are different).a.7 b.6 c.5 d. none of these

You are given n ( ge 3) circles having different radical axes and radical centres. The value of 'n' for which the number of radical axes is equal to the number of radical centres is

You are given n ( ge 3) circles having different radical axes and radical centres. The value of 'n' for which the number of radical axes is equal to the number of radical centres is

Let there be n circles no three of which have collinear centres.If the total number of radical axes is equal to total number of possible radical centres,then possible value of n is

ln n(n>=3) circles the centres of no three circles are collinear. If the number of the radical axes of the circles is equal to the number of the radical centres of the circles then n^(2)-4n-5=

STATEMENT-1 : If n circles (n ge 3) , no two circles are non-centric and no three centre are collinear and number of radical centre is equal to number of radical axes, then n = 5. and STATEMENT-2 : If no three centres are collinear and no two circles are concentric, then number of radical centre is ""^(n)C_(3) and number of radical axs is ""^(n)C_(2).

STATEMENT-1 : If n circles (n ge 3) , no two circles are non-centric and no three centre are collinear and number of radical centre is equal to number of radical axes, then n = 5. and STATEMENT-2 : If no three centres are collinear and no two circles are concentric, then number of radical centre is ""^(n)C_(3) and number of radical axs is ""^(n)C_(2).

The radical center of three given circles will be the center of a fourth circle which cuts all the three circles orthogonally.

The total number of divisor of 480 that are of the form 4n+2,ngeq0, is equal to a. 2 b. 3 c. 4 d. none of these

The total number of divisor of 480 that are of the form 4n+2,ngeq0, is equal to a. 2 b. 3 c. 4 d. none of these