Assuming the earth to be a homogeneous sphere of radius `R`, its density in terms of `G` (constant of gravitation) and `g` (acceleration due to gravity on the surface of the earth)

Assuming the earth to be a homogencous sphere of radius R. its density in terms of G (constant of gravitation) and g (acceleration due to gravity on the surface of the earth )is

If R is the radius of the earth and .g. the acceleration due to gravity, the mass of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

Find the height (in terms of R, the radius of the earth) at which the acceleration due to gravity becomes g/9(where g=the acceleration due to gravity on the surface of the earth) is