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For a first order reaction 75% reaction ...

For a first order reaction 75% reaction complete in 90 min. for the same reaction 60% complete in what time?

A

45 min

B

37 min

C

60 min

D

40 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the time taken for 60% completion of a first-order reaction, given that 75% completion takes 90 minutes. We will use the first-order reaction kinetics formula. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - For a first-order reaction, the relationship between time and concentration is given by the equation: \[ t = \frac{2.303}{k} \log \frac{[A_0]}{[A]} \] - Here, \( [A_0] \) is the initial concentration, and \( [A] \) is the concentration at time \( t \). 2. **Setting Up the Known Values**: - Given that 75% of the reaction is complete in 90 minutes, we can find the remaining concentration: - Initial concentration, \( [A_0] = 100\% \) - Remaining concentration after 75% completion, \( [A] = 100\% - 75\% = 25\% \) - Therefore, we can write: \[ t_{75\%} = 90 \text{ minutes} \] 3. **Applying the Formula for 75% Completion**: - Using the formula for \( t_{75\%} \): \[ 90 = \frac{2.303}{k} \log \frac{100}{25} \] - Simplifying the logarithm: \[ \log \frac{100}{25} = \log 4 = 2 \log 2 \approx 2 \times 0.301 = 0.602 \] - Thus, we can rewrite the equation: \[ 90 = \frac{2.303}{k} \times 0.602 \] 4. **Setting Up the Equation for 60% Completion**: - Now, we need to find the time for 60% completion: - Remaining concentration after 60% completion, \( [A] = 100\% - 60\% = 40\% \) - Using the formula for \( t_{60\%} \): \[ t_{60\%} = \frac{2.303}{k} \log \frac{100}{40} \] - Simplifying the logarithm: \[ \log \frac{100}{40} = \log 2.5 \approx 0.398 \] 5. **Dividing the Two Equations**: - To eliminate \( k \), we can divide the two equations: \[ \frac{t_{60\%}}{t_{75\%}} = \frac{\log \frac{100}{40}}{\log \frac{100}{25}} \] - Substituting the values: \[ \frac{t_{60\%}}{90} = \frac{0.398}{0.602} \] - Cross-multiplying gives: \[ t_{60\%} = 90 \times \frac{0.398}{0.602} \approx 59.48 \text{ minutes} \] 6. **Final Answer**: - The time taken for 60% completion is approximately 59.48 minutes. Rounding this, we find the closest option is: \[ \text{Answer: } 60 \text{ minutes} \]
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