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[" If "p=(5)/((1+k)^(2))" ,then nequals-...

[" If "p=(5)/((1+k)^(2))" ,then nequals- "],[[" (a) "log(5)/(p(1+k))," (b) "(log(3/p))/(log(1+x))," (c) "(log(1+k))/(log(1+k))," (d) "(log(1+x))/(log(3/p))]]

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Let P(k)=(1+cos(pi/(4k))) (1+cos(((2k-1)pi)/(4k))) (1+cos(((2k+1)pi)/(4k)))(1+cos(((4k-1)pi)/(4k)))dot Then Prove that (a) P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) (c) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)

Let P(k)=(1+cos(pi/(4k))) (1+cos(((2k-1)pi)/(4k))) (1+cos(((2k+1)pi)/(4k)))(1+cos(((4k-1)pi)/(4k)))dot Then Prove that (a) P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) (c) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)

Let P(k)=(1+cos(pi/(4k))) (1+cos(((2k-1)pi)/(4k))) (1+cos(((2k+1)pi)/(4k)))(1+cos(((4k-1)pi)/(4k)))dot Then (a) P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) (c) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)

p(x) = x^(2)-x+k, p(1) = -1 then k = …………

If (2)/(3),k,(5)/(8) are in A.P.find the value of k

The equilibrium constant for the reaction? P_(4(s)) +5 O_(2(g)) rarr P_(4)O_(10(s)) (A) k_(p) =(1)/ (p_(o_(2))^(5)) (B) k_(p) = p_(o_(2))^(5) (C) k_(p) = (P_(P_(4)o_(10))) / (p_(p_(4)) p_(o_(2))^(5)) (D) k_(p) = (p_(p_(4)) * p_(o_(2))^(5)) / (P_(p_(4)o_(10))) ]

Let P(k)=(1+cos((pi)/(4k)))(1+cos(((2k-1)pi)/(4k)))(1+cos(((2k+1)pi)/(4k)))(1+cos(((4k-1)pi)/(4k))) Then (a)P(3)=(1)/(16) (b) P(4)=(2-sqrt(3))/(16)P(5)=(3-sqrt(5))/(32)( d) P(6)(2-sqrt(3))/(16)

Let P(k)=(1+cospi/(4k)) (1+cos((2k-1)pi)/(4k)) (1+cos((2k+1)pi)/(4k))(1+cos((4k-1)pi)/(4k))dotT h e n P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)

Let P(k)=(1+cospi/(4k)) (1+cos((2k-1)pi)/(4k)) (1+cos((2k+1)pi)/(4k))(1+cos((4k-1)pi)/(4k))dotT h e n P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)

If -5, k, -1 are in A.P., then the value of k is equal to