" 19.(i) "int tan^(-1)((2x)/(1-x^(2)))dx

If I = int tan^(-1)((2x)/(1-x^(2)))*dx then I-2x*tan^(-1)x =

If I_(1) int sin^(-1) ((2x)/(1 +x^(2)) ) dx , I_(2) = int cos^(-1) ((1-x^(2))/(1 +x^(2)) ) dx , I_(3) = int tan^(-1) ((2x)/(1 - x^(2)) ) dx , then I_(1) + I_(2) - I_(3) =

If I_(1)= int Sin^(-1)((2x)/(1+x^(2)))dx,I_(2)= int Cos^(-1)((1-x^(2))/(1+x^(2)))dx, I_(3)= intTan^(-1)((2x)/(1-x^(2)))dx then the value of I_(1)+I_(2)-I_(3)=

int (tan^(-1)x)^(2)/(1+x^2)dx

Evaluate int tan ^(-1)((2x)/(1-x^(2)))dx on I sub R \\{-1, 1}.

Evaluate: int tan^(-1)((2x)/(1-x^(2)))dx

Evaluate int tan^(-1)((2x)/(1-x^(2))) dx

int(x tan^(-1)x^(2))/(1+x^(4))dx

int(x^(2)tan^(-1)x)/(1+x^(2))dx