`25x^2-10x+1-36y^2`

Factorize each of the following expressions : 25 x^2-10 x+1-36 y^2

Factorize each of the following expressions: (a) a^2-b^2-a-b (b) 25 x^2-10 x+1-36 y^2 (c) 1-2a b-(a^2+b^2)

If the reflection of the ellipse ((x-4)^(2))/(16)+((y-3)^(2))/(9) =1 in the mirror line x -y -2 = 0 is k_(1)x^(2)+k_(2)y^(2)-160x -36y +292 = 0 , then (k_(1)+k_(2))/(5) is equal to

If the reflection of the ellipse ((x-4)^(2))/(16)+((y-3)^(2))/(9) =1 in the mirror line x -y -2 = 0 is k_(1)x^(2)+k_(2)y^(2)-160x -36y +292 = 0 , then (k_(1)+k_(2))/(5) is equal to

If the reflection of the ellipse ((x-4)^(2))/(16)+((y-3)^(2))/(9) =1 in the mirror line x -y -2 = 0 is k_(1)x^(2)+k_(2)y^(2)-160x -36y +292 = 0 , then (k_(1)+k_(2))/(5) is equal to

A focus of the hyperbola 25x^(2)-36y^(2)=225 is

{:("Column" A ,, "Column" B), (225x^(2) - 625 y^(2) = ,, (a) 25(x-2) (x-2)), (x^(2) - x - y - y^(2) = ,, (b) 25(3x- 5y) (3x + 5y)), (x^(2) - x - y^(2) + y = ,, (x + y) (x - y- 1)), (25x^(2) - 100 x + 100 = ,, (d) (x - y) (x + y -1)), (,,(e) (x + y) (x + y - 1)):}

Is x^2 - 6xy + 36y^2 a perfect square trinomial ?

The foci of the ellipse 25x^2+36y^2=225 are

Find the axes,eccentricity,lsatus rectum and the coordinates fo the foci of the hyperbola 25x^(2)-36y^(2)=225