" 14."int(cos2x-cos2 theta)/(cos x-cos theta)dx" is equal to "

int(cos 2x - cos 2 theta)/(cos x - cos theta)dx is equal to

int (cos2x-cos2theta)/(cosx-costheta)dx is equal to

int(cos2x-cos2theta)/(cosx-costheta)dx is equal to

int (cos2x - cos 2theta)/(cosx- costheta)dx is equal to

int(cos2x-cos2 theta)/(cos x-cos theta)dx is equal to 2(sin x-cos theta)+C(b)2(sin x+x cos theta)+C(b)2(sin x-x cos theta)+C(d)2(sin x+2x cos theta)+C(d)2(sin x-2x cos theta)+C

Evaluate: int(cos2x-cos2 theta)/(cos x-cos theta)dx

int(cos 2x-cos 2 theta)/(cosx-cos theta)dx=....+C

Evaluate: int(cos2x-cos2theta)/(cosx-costheta)dx

Evaluate: int(cos2x-cos2theta)/(cosx-costheta)dx