int(px^(p+2q-1)-qx^(q-1))/(x^(2p+2q)+2x^(p+q)+1)dx

If x is nearly equal to 1 show that (a) (px^(p)-qx^(q))/(p-q)=x^(p+q) (nearly) (b) (px^(q)-qx^(p))/(x^(q)-x^(p)) =(1)/(1-x) (nearly) (Hint : Take x=1+delta x and proceed)

int((p+q tan^(-1)x))/(1+x^(2))dx

If x nearly equal to 1 show that (px^p - qx^q)/(p-q) = x^(p+q) (nearly)

If x nearly equal to 1 show that (px^p - qx^q)/(p-q) = x^(p+q) (nearly)

If P(x)=intx^(3)/(x^(3)-x^(2))dx, Q(x)=int1/(x^(3)-x^(2))dx " and " (P+Q)(2)=5/2, " then " P(3)+Q(3)=

If P(x)=intx^(3)/(x^(3)-x^(2))dx, Q(x)=int1/(x^(3)-x^(2))dx " and " (P+Q)(2)=5/2, then P(3)+Q(3)=

Prove that px^(q - r) + qx^(r - p) + rx^(p - q) gt p + q + r where p,q,r are distinct number and x gt 0, x =! 1 .

The base BC of a hat ABC is bisected at the point (p,q)& the equation to the side AB&AC are px+qy=1&qx+py=1. The equation of the median through A is: (p-2q)x+(q-2p)y+1=0(p+q)(x+y)-2=0(2pq-1)(px+qy-1)=(p^(2)+q^(2)-1)(qx+py-1) none of these

If x nearly equal to 1 show that (px^q - qx^p)/(x^q - x^p) = (1)/(1 -x) ( nearly)