A particle is moving along a circular path with a constant speed `30m//s`. What is change in velociyt of a particle, when it describe and angle of `90^(@)` at the centre of the circle

If a particle is moving along a circular path with constant speed, then Its motion is

A particle is moving on a circular path with a constant speed v . Its change of velocity as it moves from A to B is:

A particle is moving on a circular path with constant speed v. The magnitude of the change in its velocity after it has described an angle of 90^(@) is :

A particle is moving on a circular path with constant speed v. The magnitude of the change in its velocity after it has described an angle of 90^(@) is :

A particle is moving on a circular path with a constant speed 'v'. Its change of velocity as it moves from A to B is:

A particle is moving on a circular path with constant speed, then its acceleration will be

A particle is moving on a circular path with constant speed, then its acceleration will be

A particle is moving along a circular path with a constant speed 10 ms^-1 .What is the magnitude of the change in velocity of the particle ,when it moves through an angle of 60^@ around the center of the circle ?

A particle is moving along a circular path with a constant speed 10 ms^-1 .What is the magnitude of the change in velocity of the particle ,when it moves through an angle of 60^@ around the center of the circle ?

A particle moves in a circular path with constant speed . Its motion is