A beam of electron accelerated by a large potential difference `V` is mode of strike a metal target of produce X-ray . For which of the following value of `V` , will the resulting X-ray have the lower minimum wavelength?

A beam of electron accelerated by a large potential difference V is mode of strike a metal target of produce X-ray . For what value of V , will the resulting X-ray have the lower minimum wavelength?

In producing X-rays a beam of electrons accelerated by a potential difference V is made to strike a metal target. For what value of V,X -rays will have the lowest wavelength of 0.3094 Å

An electron beam is accelerated by a potential difference V to hit a metallic target to produce X- rays. It produces continuous as well as characteristic X - ray. If lambda_("min") is the smallest possible wavelength of X-ray in the spectrum, the varistion of log lambda_("min") with log V is correctly represented in

An electron beam is acceleration by a potential difference V to hit a metallic target to produce X-rays. It produces continuous as well as characteristic X-rays. If lambda_(min) is the smallest possible wavelength of X-rays in the spectrum, the variation of log lambda_(min) with log v is correctly represented in

An electron beam is acceleration by a potential difference V to hit a metallic target to produce X-rays. It produces continuous as well as characteristic X-rays. If lambda_(min) is the smallest possible wavelength of X-rays in the spectrum, the variation of log lambda_(min) with log v is correctly represented in

In a X - ray tube , electrons accelerated through a very high potential difference strike a metal target . If the potential difference is increased , the speed of the emitted X - rays :