Given `tanA=4/3` then find `(cosecA)/(cosA-secA)`

If sin A=(3)/(4) and A is not in the first quadrant, then find (cosA+cos2A)/(tanA+secA) .

tan A +cotA =secA.cosecA

If sinA=1/3 then cosA. cosecA+tanA.secA=

If secA+tanA=3/2 then

Find (1+tanA +secA)(1+cotA-cosecA) .

(tanA+secA-1)/(tanA-secA+1)=

If 3tanA=4 then cosA = ………….

Prove the following identities. where the angles involved are acute angles for which the expressions are defined. (cosecA-sinA)(secA-cosA)=1/(tanA+cotA) [ Hint: Simplify LHS and RHS separately ]