Calculate the enthalpy change for the process
`C Cl_(4)(g) rarr C(g)+4Cl(g)`
and calculate bond enthalpy of `C-Cl` in `C Cl_(4)(g)`.
`Delta_(vap)H^(Θ)(C Cl_(4))=30.5 kJ mol^(-1)`
`Delta_(f)H^(Θ)(C Cl_(4))=-135.5 kJ mol^(-1)`
`Delta_(a)H^(Θ)(C )=715.0 kJ mol^(-1)`, where `Delta_(a)H^(Θ)` is enthalpy of atomisation
`Delta_(a)H^(Θ)(Cl_(2))=242 kJ mol^(-1)`

Calculate the enthalpy change for the process "CC"l_(4)(g)toC(g)+4CI(g) and calculate bond enthalpy of C-Cl in C Cl_(4)(g). Delta_("vap")H^(theta)("C C"l_(4))=30.5 kJ mol^(-1) . Delta_(f)H^(theta)(CCl_(4))=-135.5 kJ mol^(-1) . Delta_(0)H^(theta)(C)=715.0 kJ mol^(-1) , where Delta_(a)H^(theta) is enthalpy of atomisation. Delta_(a)H^(theta)(Cl_(2))=242 kJ mol^(-1) .

Calculate the enthalpy change for the process 'CCl_4(g) rarr C(g)+4 Cl(g)' and calculate bond enthalpy of 'C-Cl' in 'CCl_4(g)' 'Delta_(vap) H_^0 (C C l_4)=30.5 kJ mol ^(-1)' 'Delta_f H^0(C C l_4)=(-1)35.5 kJ mol^(-1)' 'Delta_n H^0(C)=715.0 kJ mol^(-1)', where 'Delta_n H^0' is enthalpy of atomisation, 'Delta_n H^ (Cl_2)=242 kJ mol^(-1)'

Calculate the enthaply change for the process : C Cl_4 (g) to C (g)+ 4Cl(g) and calculate the bond enthalpy of C-Cl in C Cl_4(g) triangle(vap))H^(@) (C Cl_4 )= 30.5 kJ mol^-1 trianglef H^(@)(C Cl_4) = -135.5 kJ mol^-1 triangle_a H^@(C) = 715.0 kJ mol^-1 triangle_a H^@(Cl_2)( atomisation ) = 242 kJ mol^-1

Calculate the enthalpy change for the reaction H_(2)(g) + Cl_(2)(g) to 2HCl(g) . The bond enthalpy of H - H, Cl - Cl and H - Cl ar 437, 244 and 433 kj mol^(-1) respectively.

Cl_2(g)rarr 2Cl(g) Delta H^@=242KJ mol^(-1) what is its enthalpy of atomization?