If `u=(1+cos theta)(1+cos 2theta)-sin theta.sin 2theta, v=sin theta(1+cos 2theta)+sin 2theta(1+cos theta)`, then `u^(2)+v^(2)=`

If u = (1 + cos theta) (1+ cos2 theta) - sin theta sin 2theta, v = sin theta (1 + cos2 theta) + sin 2 theta(1 + cos theta), "show that" u^(2) + v^(2) = 4(1 + cos theta) (1 + cos 2theta).

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

((sin theta+cos theta)^(2)-1)/(sin theta*cos theta)

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

(xv) (cos^2 theta) / (1- tan theta) +( sin^3 theta)/ (sin theta - cos theta) = 1 + sin theta cos theta

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?