If `P_n` denotes the product of all the coefficients of `(1+ x)^n and 8! P_(n+1)=9^8 P_n` then `n` is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients in the expansion of (1+x)^(n), n in N , show that, (P_(n+1))/(P_(n))=((n+1)^(n))/(n!) .

If n be a positive integer and P_n denotes the product of the binomial coefficients in the expansion of (1 +x)^n , prove that (P_(n+1))/P_n=(n+1)^n/(n!) .