The K.E. of `alpha`-particle incident gold foil is doubled. How does the distance of closest approach change?

Calculate the energy of an a-particle if in a collision of this particle with gold nucleus, the distance of closest approach is 4.95 xx 10^(-12) m.

The distance of closest approach of an alpha -particle fired at nucleus with momentum p is d. The distance of closest approach when the alpha -particle is fired at same nucleus with momentum 3p will be

(a) Define the distance of closest approach. A alpha -particle of kinetic energy K is bombarded on a thin gld foil. The distance of the closest approach is r_(a) . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ? (b) Show that the radius of the orbit of an electron in hydrogen atoms varies as n^(2) , where n is the principal quantum number of the atom.

The distance of closest approach of an alpha -particle fired at nucleus with momentum p is d. The distence of closest approach when the alpha -particle is fired at same nucleus with momentum 3p will be