Show that `3 log 4 -2 log 6+ log (18)^(3/2)= log 96sqrt( 2) `

Show that 3log4-2log6+log(18)^((3)/(2))=log96sqrt(2)

(i) Show that (log 9)/2 + 2 log 6 +(log 81)/4 - log 12 = 3 log 3 .

If log 2 = 0.3010 and log 3 = 0.4771, find the value of : (i) log 6 (ii) log 5 (iii) log sqrt(24)

(i) Show that (log9)/(2)+2log6+(log81)/(4)-log12=3log3

Express in terms of log 2 and log 3 : log ""(sqrt(54) xx ""^(3) sqrt(243))

Show that |(log x, log y, logz),(log 2x, log2y, log2z),(log3x, log3y,log3z)|=0

Show that (1)/(2)log9+2log6+(1)/(4)log81-log12=3log3

[[log e, log e ^ (2), log e ^ (3) log e ^ (2), log e ^ (3), log e ^ (4) log e ^ (3), log e ^ (4) ), log e ^ (5)]]

Prove that : "2 log" (15)/(18) - "log" (25)/(162) + "log" (4)/(9) = log 2