Fill in the blanks: `125\ x\ 27 3=3\ x dot` (ii) `8\ x =8 3` `1728 3=4\ x ` (iv) `480 3=\ 3 3\ x\ 2\ x\ 3` `\ 3=7 3\ x\ 8 3` (vi) `3=\ 4 3\ x\ 5 3\ x\ 6 3` `(27)/(125)3=\ /5` (viii) `(729)/(1331)3=9/` `(512)/3=8/(13)`

(i) ∛(125×27) = 3 × ...... (ii) ∛(8×…..) = 8 (iii) ∛1728 = 4 × ….. (iv) ∛480 = ∛3×2× ∛...... (v) ∛….. = ∛7 × ∛8

Show that: 27 3x\ 64 3=\ 27 x\ 64 3 64 x\ 729 3=\ 64 3x\ 729 3 -125 x\ 216 3=\ -125 3x\ 216 3 -125 3x-1000=-125 3x\ -1000 3

if 4 x 9 x 3 = 4 and 5 x 3 x 1 = 3 then 8 x 10 x 7 = ?

Solve for x - (2x+3)/7-(3x-3)/3= (2x-3)/5-8

Find the value of 27 x^3+\ 8y^3, if (i) 3x+2y=14 and x y=8 (ii) 3x+2y=20\ and x y=(14)/9

Facorise: 125-8x^3-27y^3-90xy

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

If 5x - 4y = 7 and xy =8 , find : 125x^3 - 64y^3 .

Solve 3x^(4) -8x^(3) -6x^(2) + 8x + 3 = 0 .

Simplify: ((3)/(2)x(1)/(6))+((5)/(3)x(7)/(2))-((13)/(8)x(4)/(3))