The circuit is switched on at `t=0`, Find the time when energy stored in inductor becomes `1/n` tiimes of maximum energy stored in it:

Energy Stored In An Inductor

The capacitor shown in the figure is initially unchanged, the battery is ideal. The switch S is closed at time t= 0, then the time after which the energy stored in the capacitor becomes one - fourth of the energy stored in it in steady - state is :

A charged capacitor is connected to an inductor . At a particular instant, energy stored in inductor is 8/9 times of initial energy stored In capacitor . What is the ratio of initial charge on capacitor to that with instantaneous charge on capacitor ?

A simple LR circuit is connected to a battery at time t = 0 . The energy stored in the inductor reaches half its maximum value at time

Figure-5.150 shows LC circuit with initial charge on capacitor 200 mu C . If at t=0 switch is closed, find the first instant when energy stored in inductor becomes one third that of capacitor.

At t=0 switch S is closed . (a) After how much time , charge on capacitor is 50% of maximum charge stored on capacitor. (b) After how much time, energy stored in capacitor is halt of maximum energy stored in capacitor.

A circuit contains 50 muF capacitor and 20 mH inductor connected together with the help of a key which is open initially. Charge stored in the capacitor is 50 mC. Key is closed at t=0 . Calculate the minimum time interval in which energy stored in the inductor becomes equal to the energy stored in capacitor . Neglect any resistance in the circuit .