The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of `water = 10^3 kg/m^3, g=9.8 m/s^2` at Calcutta. Pressure `=h rho g` in usual symbols.

The height of mercury column in a barometer in the Kolkata laboratory was recorded to be 75 cm. Calculate the pressure at Kolkata in SI unit using the following data: Density of mercury = 13.6xx10^(3)kgm^(-3) , pressure = rhogh , where h is the height of mercury column, rho is the density of mercury, and g is the acceleration due to gravity)

A mercury barometer in a physics laboratory shows a 732 mm vertical column of mercury. Calculate the atmospheric pressure in pascal. [Given density of mercury , rho = 1.36 xx 10^(4) kg m^(-3) , g = 9.8 m s^(-2) ]

Calculate the total pressure at the bottom of a lake of depth 5.1 m (atm pressure =10^(5) P), density of water =10^(3)kg//m^(3),g=10m//s^(2)

A swimmer is swimming in a swimming pool at 6 m below the surface of the water. Calculate the pressure on the swimmer due to water above. (Density of water = 1000 kg/m^3, g = 9.8m/s^2)

Density of mercury is 13.6 g cm^(-3) . Its density in kg m^(-3) is

Calculate the pressure due to a water column of height 100 m. (Take g=10 ms^(-2) and density of water =10^(3)kg m^(-3)) .

The velocity of sound in air at 0^@C is [rho=1.29 kg m^(-3) lambda=1.36 , density of mercury= 13000 kg//m^3 , g=9.8 m//s^2] .

A barometer kept in an alevator ac celerating upward reads 76 cm of mrecury. If the elevator is ac celerating upwards at 4.5ms^(-2) find the air pressure in the elevator in cm of mercury. Density of mercuty =13.6 xx 10^3 kg m^(-3) G = 9.8 m//s^2