If sum of the roots of the quadratic equation, `a x^2+b x+c=0i s12 ,` then the sum of the roots of the equation, `a(x+1)^2+b(x+1)+c=0` is: a. 9 b. 10 c. 12 d. 14

If sum of the roots of the quadratic equation, a x^2+b x+c=0 is 12 , then the sum of the roots of the equation, a(x+1)^2+b(x+1)+c=0 is: (a) 9 (b) 10 (c) 12 (d) 14

If sum of the roots of the quadratic equation,ax^(2)+bx+c=0 is 12, then the sum of the roots of the equation,a(x+1)^(2)+b(x+1)+c=0 is: a.9 b.10 c. 12d.14

If sum of the roots of the quadratic equation,ax^(2)+bx+c=0, then the sum of the roots of the equation,a(x+1)^(2)+b(x+1)+c=0 is: (a)9 (b) 10 (c) 12(d)14

Let alpha,beta be the roots of the quadratic equation ax^2+bx+c=0 then the roots of the equation a(x+1)^2+b(x+1)(x-2)+c(x-2)^2=0 are:-

If the sum of the roots of the equation a x^(2)+b x+c=0 is equal to the sum of the squares of their reciprocals, then

The sum of the roots of the equation 1/(x+a) + 1/(x+b) = 1/c is zero. What is the product of the roots of the equation ?

The roots of the equation (b-c)x^(2)+(c-a)x+(a-b)=0

The roots of the equation ( a-b) x^2 +(b-c) x+ (c-a) =0 are

If c, d are the roots of the equation (x-a) (x-b) - k=0 , then prove that a, b are the roots of the equation (x-c) (x-d) + k= 0