`sin2x-sin2y=`

the value of lim_(x->y) (sin^2x-sin^2y)/(x^2-y^2) equals

the value of lim_(x->y) (sin^2x-sin^2y)/(x^2-y^2) equals

(sin 2x - sin 2y)/(cos 2y-cos 2x) = cot (x+y)

the value of lim_(x->y) (sin^2x-sin^2y)/(x^2-y^2) equals

the value of lim_(x->y) (sin^2x-sin^2y)/(x^2-y^2) equals

Show that sin(x+y)sin(x-y)= sin^2 x -sin^2 y .Hence prove that sin(x+y)sin(x-y)+sin(y+z)sin(y-z) +sin(z+x)sin(z-x)=0

Show that (i) cos x+cos y=2 cos (x+y)/(2) cos (x-y)/(2) (ii) cos x-cos y=-2 sin (x+y)/(2) sin (x-y)/(2) (iii) sin x+sin y=2 sin (dot(x)+y)/(2) cos (x-y)/(2) (iv) sin x-sin y=2 cos (x+y)/(2) sin (x-y)/(2)

If x-y =(4n +1) (pi)/(4) (where n is an integer) and (x+y) is not an odd multiple of pi/2, then the value of (sin 2x -sin 2y)/(cos 2x+ cos 2y) is -

If sin^(2)x+cos^(2)y=1 , show that dy/dx=(sin2x)/(sin 2y)

If x+y+z= (pi)/(2) show that sin 2x + sin 2y + sin 2z =4 cos x cosy cos z