" (i) "sin12 theta+sin4 theta

sin4 theta.sin6 theta=

Express each of the following as the product of sines and cosines: sin12 theta+sin4 theta

( sin 2 theta + 2 sin 4 theta + sin 6 theta )/(sin 4 theta + 2 sin 6 theta + sin 8 theta ) =

Solve 4sin theta sin2 theta sin4 theta=sin3 theta

sin3 theta=4sin theta sin2 theta sin4 theta in0<=theta<=pi has

4 sin theta * cos^(3) theta-4 cos theta * sin ^(3)theta= A) 4 cos theta B) cos 4 theta C) 4 sin theta D) sin 4 theta

The value of (sin2 theta+sin4 theta)/(1+cos2 theta+cos4 theta) is equal to

Prove that ( cos theta + cos 2 theta + cos 3 theta + cos 4 theta)/(sin theta + sin 2 theta + sin 3 theta + sin 4 theta)= cot ""(5theta)/(2).

Solve the following: sin theta + sin 2 theta + sin 3 theta + sin 4 theta=0

lim_(theta rarr 0) (sin 3 theta . sin 4 theta)/(theta . sin 5 theta) =