" Let "A=[[1,-1,1],[2,1,-3],[1,1,1]]" and "10B=[[4,2,2],[-5,0,alpha],[1,-2,3]]

Let A = [(1,-1,1),(2,1,-3),(1,1,1)] and (10)B = [(4,2,2),(-5,0,alpha),(1,-2,3)] If B is the inverse of A , then alpha is :

Let A=[(1,-1,1),(2,1,-3),(1,1,1)] and B=[(4,2,2),(-5,0,alpha),(1,-2,3)] If B is the inverse of matrix A , then alpha= (A) 2 (B) -2 (C) 5 (D) -5

Let A=((1,-1,1),(2,1,-3),(1,1,1)) and (10) B=((4,2,2),(-5,0,alpha),(1,-2,3)) . If B is the inverse of matrix A, then alpha is

If inverse of A=[{:(1,-1,1),(2,1,-3),(1,1,1):}] is (1)/(10)[{:(4,2,2),(-5,0,alpha),(1,-2,3):}] then alpha =…..

Let A=[[2,1,3],[4,1,0]] and B=[[1,-1],[0,2],[5,0]] Find AB

let A=[[1,0,5],[2,-1,3],[4,1,0]] and B=[[3,2,1],[0,2,1],[3,2,5]] find A',B' and (A+B)' show that (A+B)'=A'+B'