" If "3sin x+4cos x=5" then "6tan(x)/(2)-9tan^(2)(x)/(2)=

If 3sin x+4cos x=5, then 6(tan)(x)/(2)-9(sin)^(2)(x)/(2)=

3sinx+4cosx=5implies6tan""(x)/(2)-9tan^(2)""(x)/(2) =

3 sin x+ 4 cos x= 5implies 6 tan""(x)/(2)-9 tan^(2)""(x)/(2)=

If 3sin x+4cos x=5 then the value of tan backslash((x)/(2)) is

Evaluate the following integrals: int{3sin x-4cos x+(5)/(cos^(2)x)-(6)/(sin^(2)x)+tan^(2)x-cot^(2)x}dx

If 2sin x+5cos y+7sin z=14 then 7tan((x)/(2))+4cos y-6cos z=

Evaluate: (i) int(1-cos x)/(1+cos x)dx (ii) int{3sin x-4cos x+(5)/(cos^(2)x)-(6)/(sin^(2)x)+tan^(2)x-cot^(2)x}dx

tan4x=(4tan x(1-tan^(2)x))/(1-6tan^(2)x+tan^(4)x)

tan4x=(4tan x(1-tan^(2)x))/(1-6tan^(2)x+tan^(4)x)