The instantaneous rate of change at `t=1` for the function `f(t)=te^(-1)+9` is

The function f (t) = tan t -t :

The rate of change of the function y = f(x) w.r.t. X at the point x is-

A body of mass m , accelerates uniformly from rest to V_(1) in time t_(1) . The instantaneous power delivered to the body as a function of time t is.

A body of mass m , accelerates uniformly from rest to V_(1) in time t_(1) . The instantaneous power delivered to the body as a function of time t is.

A body of mass m , accelerates uniformly from rest to V_(1) in time t_(1) . The instantaneous power delivered to the body as a function of time t is.

Let f(x)=x^(2)-4x+7 1. Find the instantaneous rate of change of f at x = 3. 2. Find the average rate of change of f with respect to x between x = 3 and 5.

Volume of cone with semi vertical angle tan^(-1)(1/3) is increasing at a rate of 9picm^(3)//sec when radius of cone is 1cm .The instantaneous rate of change of height at this time is : (in cm/sec)

For the functions f(x) = x^(2) , x in [0, 2] compute the average rate of changes in the subintervals [0,0.5], [0.5, 1], [1, 1.5], [1.5, 2] and the instantaneous rate of changes at the points x = 0.5 , 1, 1.5, 2

Differentiate the function f(t)=sqrt(t)(1-t)