[" A body is projected veritcally upwards.If "t_(1)" and "t_(2)" be the time at which it is at height habove the "],[" projection while ascending and descending respectively.then "h" is "],[[" a) "(1)/(2)gt_(1)t_(2)," b) "gt_(1)t_(2)," c) "2g_(1),t_(2)," d) "2hg]]

A body is projected verticallt upwards. If t_(1) and t_(2) be the times at which it is at a height h above the point of projection while ascending and descending respectively, then:

A body is vertically upwards. If t_(1) and t_(2) are the times at which it is height h above the point of projection while ascending and descending, respectively, find (a) the velocity of projection and height h, (b) the maximum height reached by the body and (c ) the velocity of the body at height h//2 .

A stone is projected vertically upwards. Its height h at time t sec is h=(80)t-(16)t^(2) . The velocity with which it hits the ground is

A body is projected vertically upwards and attains maximum height H. If the time to reach height 'h' and H are in the ratio of 1:3, then the ratio h/H is :

A body is projected vertically upwards . The times corresponding to height h while ascending and while descending are t_(1)andt_(2) respectively . Then the velocity of projection is (g is acceleration due to gravity)

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time t (lt T) will be