20." यदि "x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta)," दो "(dy)/(dx)" ्ञात कीजिए। "

If x = a(cos theta + theta sin theta), y = a (sin theta - theta cos theta), (dy)/(dx) =

If x = a(cos theta + theta sin theta), y = a (sintheta - theta cos theta), dy/dx =

If x =a (cos theta +theta sin theta ), y =a (sin theta -theta costheta ) ,then (dy)/(dx) =

If x =a (cos theta + theta sin theta ), y =a (sin theta - theta cos theta ) then (dy)/(dx) =

x = a (cos theta + theta sin theta), y = a (sin theta - theta cos theta) . then find dy/dx

If x = a (cos theta + theta sin theta), y = a(sin theta - theta cos theta) then (d^(2)y)/(dx^(2)) =

Find dy/dx : x = cos theta + sin theta, y = sin theta - theta cos theta

Consider the curve x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta). What is (dy)/(dx) equal to? What is (d^(2)y)/(dx^(2)) equal to?