The equation of the line AB is `y = x`. If A and B lie on the same side of the line mirror `2x-y = 1`, then the equation of the image of AB is

The equation of the line segment AB is y=x . If A and B lie on same side of the line mirror 2x-y=1 , then image of AB has the equation

The equation of a line AB is 2x - 2y + 3 = 0. Find the slope of the line AB.

The equation of the image of the lines y=|x| in the line mirror x = 2 is

The equation of the image of the lines y=|x| in the line mirror x = 2 is

The equation of a line AB is 2x - 2y + 3 = 0. Calculate the angle that the line AB makes with the positive direction of the x-axis.

The given figure (not drawn to scale) shows two straight lines AB and CD. If equation of the line AB is : y = x + 1 and equation of line CD is : y = sqrt(3) x - 1 . Write down the inclination of lines AB and CD, also, find the angle theta between AB and CD.

If the equation of the line AB is (3 - x)/1=(y + 2)/-2=(z - 5)/4 then write the d.r.s of the line parallel to AB.

The equation of the image of line y=x wire respect to the line mirror 2x-y=1 is

The equation of the image of line y=x wire respect to the line mirror 2x-y=1 is