-2x^(2)y-15xy^(2)

If one of the lines 2x^(2)-xy-15y^(2)=0 is perpendicular to line kx+y=0 then k=

The factors of x^(3)-x^(2)y-xy^(2)+y^(3) are (a (x+y)(x^(2)-xy+y^(2))(b)(x+y)(x^(2)+xy+y^(2))(c)(x+y)^(2)(x-y)(d)(x-y)^(2)(x+y)

The combined equation of the line passing through origin and perpendicular to 2x^(2)-7xy-15y^(2)=0 is

The combined equation of the line passing through origin and perpendicular to 2x^(2)-7xy-15y^(2)=0 is

The figure formed by the pairs of lines 2x^(2)+3xy-2y^(2)=0 and 2x^(2)+3xy-2y^(2)-5x+15y-25=0 is a

Simplify: 2x^(2)+3xy -3y^(2)+x^(2)-xy+y^(2)

Using horizontal method : Add x^(2)+y^(2)- 2xy , -2x^(2)-y^(2)-2xy and 3x^(2) +y^(2) +xy

x-x^(2)y+xy^(2)-y

solve: -2 (x^(2) - y^(2) + xy) - 3 (x^(2) + y^(2) - xy)