" b) "a^(2)-12a-16

Factorise (Using factor theorem ) : a^(3)-12a-16

Factorise : a^(3)-12a-16

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 yz - 20xz (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 xy - 20xy (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 yz - 20zx (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 yz - 20zx (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

The equation of the circle passing through the origin which cuts of intercept of length 6 and 8 from the axes is x^(2)+y^(2)-12x-16y=0 b.x^(2)+y^(2)+12x+16y=0cx^(2)+y^(2)-3x+4y=2=0 d.none of these

The points on the curve y=12x-x^3 at which the gradient is zero are:- (a) (0,12),(2,16) (b) (0,-2),(2,-16) (c) (2,-16),(-2,16) (d) (2,16),(-2,-16)

The equation 9 x^(2)+24 x y+b^2 y^(2)-12 x+16 y-12=0 represents a pair of parallel lines then b=

In each case, find whether the trinomial is a perfect square or not : 9b^(2) + 12b +16