" s) "int_(1)^(3)(x-1)+|x-2|+|x-3|dx

int_(1)^(3)(|x-1|)/(|x-2|+|x-3|)dx=

int_(1)^(3)(2x+1)dx

int_(1)^(3)(x-1)(x-2)(x-3)dx=

int_(1)^(3)(x-1)(x-2)(x-3)dx=

int_(1)^(3)(x-1)(x-2)(x-3)dx=

int_(1)^(2) (x^3+1) dx

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

int_(-1)^(1)x^(3)|x|dx

Evaluate: int_0^1|5x-3|dx (ii) int_0^pi|cosx|dx (iii) int_(-5)^5|x-2|dx (iv) int_(-1)^1e^(|x|)dx (v) int_0^2|x^2+2x-3|dx (v) int_1^4(|x-1|+|x-2|+|x-3|)dx (vi) int_(-1)^2|x^3-x|dx