+2+3+...............+n=(n(n+1))/(2)

1^(2)+2^(2)+3^(2)+............+n^(2)=(n(n+1)(2n+1))/6 forall n in N.

1^(2)+2^(2)+3^(2)+..........+n^(2)=(n(n+1)(2n+1))/(6)

1*2+2*2^(2)+3*2^(3)+..........+n*2^(n)=(n-1)2^(n+1)+2

P(n) : 1^(2) + 2^(2) + 3^(2) + .......+ n^(2) = n/6(n+1) (2n+1) n in N is true then 1^(2) +2^(2) +3^(2) + ........ + 10^(2) = .......

By ........in "Principle of Mathematical Induction" prove that for all n in N 1^2+2^2+3^2+.......+n^2=(n(n+1)(2n+1))/(6)

By the principle of mathematical induction, prove that, for nge1 1^(3) + 2^(3) + 3^(3) + . . .+ n^(3)=((n(n+1))/(2))^(2)

By principle of mathematical induction,prove that 1^(3)+2^(3)+3^(3)+ . . .. +n^(3)=[(n(n+1))/(2)]^(2) for all ninNN

Applying the principle of mathematical induction (P.M.I.) prove that 1^2+2^2+3^2+.......+n^2=(n(n+1)(2n+1))/6

Prove the following by the method of induction for all n in N : 1^2 + 2^2 + 3^2 + ... + n^2 = (n(n + 1) (2n + 1)) / 6 .

Using the principle of Mathematical Induction , forall n in N , prove that 1^2+2^2+3^2+.....n^2=(n(n+1)(2n+1))/6