" If "Tan A=(17)/(18),Tan B=(1)/(35)tan Cos(A+B)

If tan A=(17)/(18),tan B=(1)/(35) then cos(A+B)=

If Tan A = (17)/(18), TanB = (1)/(35) then Cos (A+B) =

If A and B are acute angles such that tan A=(1)/(2),tan B=(1)/(3) and tan(A+B)=(tan A+tan B)/(1-tan A tan B), find A+B

If tan A =18//17 , tan B=1//35 then tan (A-B)=

If tanA=18/17 and tanB=1/35 prove that tan(A-B)=1

If sin A = (3)/(5) and cos B = (12)/(13) . Then the value of (tan A - tan B)/(1 + tan A tan B) is equal to

If tan A=(1-cos B)/(sin B), then tan2A=tan B

If tan A=(x sin B)/(1-cos B)tan B=(y sin A)/(1-y cos A) then (x)/(y)=

In Delta ABC If cos A cos B cos C=(1)/(3) then tan A tan B+tan B tan C+tan C tan A=

For all values of A and Btan(A+B)=(tan A+tan B)/(1-tan A tan B) and tan(A-B)=(tan A-tan B)/(1+tan A tan B)