" If "I_(n)=int(log x)^(n)dx" then "I_(8)+8I_(7)=

If I_(n)= int (log x)^(n)dx then I_(n)+nI_(n-1)=

If I_(n)=int_(1)^(e)(log x)^(n)dx then I_(8)+8I_(7)=

If I_(n)=int(ln x)^(n)dx then I_(n)+nI_(n-1)

If I_(n) = int (log x)^(n) dx then I_(6) + 6I_(5) =

If I_(n)= int_(1)^(e) (log x)^(n) dx then I_(8) + 8I_(7)=

If n in N and I_(n) = int (log x)^(n) dx , then I_(n) + n I_(n - 1) =

If n in N and I_(n) = int(log x)^(n) dx , then I_(n)+nI_(n-1) =

If I_(n)=int("In "x)^(n)dx, " then " I_(n)+nI_(n-1)=

If I_(m,n)=int x^(m)(logx)^(n)dx then I_(m.n)=

Obtain reduction formula for If I_(n)=int (log x) ^(n)dx, then show that I_(n) =x (log x)^(n) -nI_(n-1), and hence field int (log x) ^(4) dx.