`(cos(-A+B+C)+cos(A-B+C)+cos(A+B-C)+cos(A+B+C))/(sin(-A+B+C)-sin(A-B+C)+sin(A+B-C)+sin(A+B+C))=cotB`

(cos(-A+B+C)+cos(A-B+C)+cos(A+B-C)+cos(A+B+C))/(sin(-A+B+C)-sin(A-B+C)+sin(A+B-C)+sin(A+B+C))=cot B

Prove that: (cos(A+B+C)+cos(-A+B+C)+cos(A-B+C)+"cos"(A+B-C))/(sin(A+B+C)+sin(-A+B+C)+sin(A-B+C)-"sin"(A+B-C))=cot C

Prove that: (cos(A+B+C)+cos(-A+B+C)+cos(A-B+C)+cos(A+B-C))/(sin(A+B+C)+sin(-A+B+C)+sin(A-B+C)-sin(A+B-C))=

What is the value of cos(90 -B)sin (C-A) + sin(90 + A) cos(B+ C)- sin (90 - C) cos (A + B) ? cos(90 -B)sin (C-A) + sin(90 + A) cos(B+ C)- sin (90 - C) cos (A + B) का मान क्या है?

cos(A-D)sin(B-C)+cos(B-D)sin(C-A)+cos(C-D)sin(A-B)=0

If A,B,C are the angles of a triangle, show that, (iii) (cos A cos C + cos (A + B) cos(B + C))/(cos A sin C - sin (A + B) cos (B + C)) = cot C .

Prove that cos (A + B) cos C - cos (B + C) cos A = sin B sin (C - A)

If cos(A+B+C)=cos A cos B cos C , then (8sin(B+C)sin(C+A)sin(A+B))/(sin2A sin 2B sin 2C)=

cos(A+B)+sin C=sin(A+B)-cos C