" (ii) "6,10

Equation of the line joining (6,10) and (14,12) is :

The fraction equivalent to 1 2/3 is (a) (10)/3 (b) 3/5 (c) (10)/6 (d) 6/(10)

The fraction equivalent to 1 2/3 is (a) (10)/3 (b) 3/5 (c) (10)/6 (d) 6/(10)

The coordinates of the point of intersection of the lines (x-1)/1=(y+2)/3=(z-2)/(-2) with the plane 3x+4y+5z-25=0 is (A) (5,6,-10) (B) (5,10,-6) (C) (-6,5,10) (D) (-6,10,5)

The coordinates of the point of intersection of the lines (x-1)/1=(y+2)/3=(z-2)/(-2) with the plane 3x+4y+5z-25=0 is (A) (5,6,-10) (B) (5,10,-6) (C) (-6,5,10) (D) (-6,10,5)

Compute: (10!)/(6!10!)

Show that the triangle with vertices (6,10,10),(1,0,-5) and (6,-10,0) is a right angled triangle

Show that the triangle vertices (6,10,10), (1,0,-5) and (6,-10,0) is a right - angled triangle .

Show that the triangle with vertices (6, 10, 10), (1, 0, - 5) and (6, - 10, 0) is a right-angled triangle.