(1)/(15),(1)/(12),(1)/(10),...," to "11" term "

Find the sum of the following APs. (iv) 1/15, 1/12, 1/10, ……, ot 11 terms.

find the sum of 15 terms of The sum of the series (1)/(3)+(1)/(15)+(1)/(35)+(1)/(63)+..........oo terms,is

lim_(n to infty) ((1)/(3.7)+(1)/(7.11) +(1)/(11.15)+. . . +(n" terms ")) =

Choose the correct value of (1)/(sqrt(9)+sqrt(10))+(1)/(sqrt(10)+sqrt(11))+(1)/(sqrt(11)+sqrt(12))+ upto 91 terms from the following options

2(1)/(4)+1(1)/(3)-4(1)/(2)=?-1(1)/(12) (b) (11)/(12) (c) -(11)/(12)(d)1(1)/(12) (e) None of these

Find the sum of the following AP s:(iv)1/15,1/12,1/10,……to 12 terms.

The 11th term of the A.P. 13,15(1)/(2),18,20(1)/(2),....... is :

Find the 11th term of the sequence {(1)/(2), (1)/(3), (1)/(5), (1)/(8), (1)/(12),…} .

The value of (1-(1)/(3^(2)))(1-(1)/(4^(2)))(1-(1)/(5^(2)))ddot M(1-(1)/(11^(2)))(1-(1)/(12^(2))) is (11)/(20) (b) (13)/(15) (c) (13)/(18) (d) (15)/(16) (e) None of these

Prove that (1)/(10!) +(1)/(11!)+(1)/(12!)=(145)/(12!).