" 11."a_(1)=3,a_(n)=3a_(n-1)+2" सभी "n>1" के लिए "

Some sequences are defined as follows. Find their first four terms : (i) a_(1)=a_(2)=2, a_(n)=a_(n-1)-1, n gt 2 " " (ii) a_(1)=3, a_(n)=3a_(n-1), n gt 1

Some sequences are defined as follows. Find their first four terms : (i) a_(1)=a_(2)=2, a_(n)=a_(n-1)-1, n gt 2 " " (ii) a_(1)=3, a_(n)=3a_(n-1), n gt 1

Let a_(0)=0 and a_(n)=3a_(n-1)+1 for n ge 1 . Then the remainder obtained dividing a_(2010) by 11 is

Let a_(0)=0 and a_(n)=3a_(n-1)+1 for n ge 1 . Then the remainder obtained dividing a_(2010) by 11 is

Let a_(0) = 0 and a_(n) = 3a_(n-1) + 1 for n ge 1 . Then the remainder obtained dividing a_(2010) by 11 is -

Let a_(0)=0 and a_(n)=3a_(n-1)+1 for n ge 1 . Then the remainder obtained dividing a_(2010) by 11 is

Let a_(0)=0 and a_(n)=3a_(n-1)+1 for n ge 1 . Then the remainder obtained dividing a_(2010) by 11 is

Let a_(1)=1,a_(n)=n(a_(n-1)+1 for n=2,3,... where P_(n)=(1+(1)/(a_(1)))(1+(1)/(a_(2)))(1+(1)/(a_(3)))...*(1+(1)/(a_(n))) then Lt_(n rarr oo)P_(n)=

If a_(1) , a_(2), a_(3) , cdots ,a_(n) are in A.P. with a_(1) =3, a_(n) =39 and a_(1) +a_(2) + cdots +a_(n) =210 then the value of n is equal to

If 1,a_(1),a_(2),...,a_(n-1) are the nth roots of unity then prove that (1-a_(1))(1-a_(2))(1-a_(3))=(1-a_(n-1))=n