[" A particle of mass "m" is projected at an angle "],[" with horizontal with kinetic energy "E." The "],[" potential energy at the top of its trajectory is "],[(E)/(2)" .Find the range: "]

A body projected at an angle theta to the horizontal with kinetic energy E_k . The potential energy at the highest point of the trajectory is

A body projected at an angle theta to the horizontal with kinetic energy E_k . The potential energy at the highest point of the trajectory is

A particle m is projected at an angle with the horizontal with kinetic energy E. The potential energy at the top of its trajector is E/2. The range of the particle is (xE)/(mg) , then find the value of x is

A particle is projected at an angle of 60^(@) to the horizontal with a kinetic energy E. The kinetic energy at the highest point is

An object of mass m is projected at an angle 60^(@) (with horizontal axis) with a velocity v.Its kinetic energy at the peak of the trajectory is

A body is projected at an angle 45^@ to the horizontal with KE . 'E' . The potential energy at the highest point of flight