f(0)|[0,a,-b],[-a,0,-c],[b,c,0]|=0...

f_(0)|[0,a,-b],[-a,0,-c],[b,c,0]|=0

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Prove that: |[0,a,-b],[-a,0,-c],[ b, c,0]|=0 .

If f(x)=|[0,x-a, x-b], [x+a,0,x-c], [x+b, x+c,0]|,t h e n (a) f(a)=0 (b) f(b)=0 (c) f(0)=0 (d) f(1)=0

If Delta= |[0,b-a,c-a],[a-b,0,c-b],[a-c,b-c,0]| then Delta=

The value of the determinant of A = [(0,a,-b),(-a,0,c),(b,-c,0)] is

The value of the determinant A=[(0,a,-b),(-a,0,c),(b,-c,0)] is

If f(x)|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}| then show that f(0)=0

Show that det[[0,b-a,c-aa-b,0,c-ba-c,b-c,0]]=0

If f(x)=|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}| , then "............"

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