factorise `2x^2 +y^2 +8z^2-2sqrt(2)xy+4sqrt(2)yz-8xz`

Factorise : 2x^2+y^2+8z^2-2sqrt2xy+4sqrt2yz-8xz .

Factorise : (i) 4x^(2)+9y^(2)+16z^(2)+12xy-24yz-16xz (ii) 2x^(2)+y^(2)+8z^(2)-2sqrt(2)xy+4sqrt(2)yz-8xz

Factorise : (i) 4a^(2)+9b^(2)+16c^(2)+12ab-24bc-16ca (ii) (4)/(9)x^(2)+(9)/(16)y^(2)+(16)/(25)z^(2)-xy-(6)/(5)yz+(16)/(15)zx (iii) 2x^(2)+y^(2)+8z^(2)-2sqrt(2)xy+4sqrt(2)yz-8xz

Factorise:(i) 4x^2+9y^2+16 z^2+12 x y-24 y z-16 x z (ii) 2x^2+y^2+8z^2-2sqrt(2)x y+4sqrt(2)y z-8x z

Factorise: (i) 4x^2+9y^2+16 z^2+12 x y-24 y z-16 x z (ii) 2x^2+y^2+8z^2-2sqrt(2)x y+4sqrt(2)y z-8x z

Factorise: (i) 4x^(2)+9y^(2)+16z^(2)+12xy-24yz-16xz(ii)2x^(2)+y^(2)+8z^(2)-2sqrt(2)xy+4sqrt(2)yz-8xz

Factorise : (i) 4x^2+9y^2+16z^2+12xy-24yz-16xz (ii) 2x^2+y^2+8z^2-2sqrt2xy+4sqrt2yz-8xz

If 2x^2+y^2+8z^2-2 sqrt2 xy+4 sqrt2 yz-8zx=(Ax+y+Bz)^2 , then the value of (A^2+B^2-AB) is: यदि 2x^2+y^2+8z^2-2 sqrt2 xy+4 sqrt2 yz-8zx=(Ax+y+Bz)^2 है, तो (A^2+B^2-AB) का मान होगा ?