ln Delta ABC," if "3a=b+c," then "cot(B)/(2)*cot(C)/(2)=

In /_ABC, if 3a=b+c, then cot((B)/(2))cot((C)/(2))=

If, in Delta ABC, 3a = b + c then: cot (B/2) cdot cot (C/2) = .....

In Delta ABC,if 3a=b+c , then cot""B/2.cot""C/2 =

In a !ABC , if 3a = b + c , then cot B/2 cot C/2 =

In Delta ABC, " if" s= 2b " then " cot "" (A)/(2) cot "" ( C)/(2) =

In Delta ABC , if a=3 , b=4,c=6 then ("cot" (A)/(2)+"cot" (B)/(2)+ "cot" ( C)/(2))/("cot" A + "cot" B + "cot" C)=

In a triangle ABC , if 3a = b + c , then cot B/2 cot C/2 =

In Delta ABC, cot ""(A)/(2) +cot""(B)/(2) + cot""(C)/(2)=

In Delta ABC, if s=2b then cot""A/2 cot ""C/2 =

In any Delta ABC, prove that (b+c-a)(cot,(B)/(2)+cot,(C)/(2))=2a cot,(A)/(2)