" In "Delta ABC,(cos C+cos A)/(c+a)+(cos B)/(b)=

In a Delta ABC(cos C+cos A)/(c+a)+(cos B)/(b) is

In Delta ABC,a(b cos C-c cos B)=

In a Delta ABC,(cos A cos B)/(ab)+(cos B cos C)/(bc)+(cos C cos A)/(ca) is equal to

If in a Delta ABC,(cos A)/(a)=(cos B)/(b)=(cos C)/(c), then find the measures of angles A,B,C.

In Delta ABC, (b-a cos C)/(c-a cos B)=

In Delta ABC, cos A + cos (B-C)=

In Delta ABC, (cos A)/(c sin B)+(cos B)/( a sin C)+(cos C)/( b sin A) =

in a triangle ABC , ( cos A)/(a) = (cos B )/( b) = ( cos C )/( c ) if a=(1 )/( sqrt(6)) then the area of the triangle ( in square units ) is