A sphere of mass 0.5 kg rests at one corner of a cube. The cube is moved with velocity `v=8hati-2t^(2)hatj` where t is time in seconds. Find the magnitude of force by sphere on the cube at t=1 s is (figure shown vertical plane of the cube `g=10m//s^(2)`)

A sphere of mass 1 kg rests at one corner of a cube. The cube is moved with a velocity v =(8 t hat(i) - 2t^(2)) hat(j) , where t is time in second . The force by sphere on the cube at t = 1 s is (g = 10 m//s^(-2)) [figure shown vertical plane of the cube]

A sphere of mass 1 kg rests at one corner of a cube. The cube is moved with a velocity v =(8 t hat(i) - 2t^(2)) hat(j) , where t is time in second . The force by sphere on the cube at t = 1 s is (g = 10 m//s^(-2)) [figure shown vertical plane of the cube]

A solid sphere of mass of 2kg rests inside a cube as shown The cube is moving with ve-locity vecv = (5thati+2thatj)ms^(-1) where 't' is in sec and 'v' is in m/s What force does sphere exert on cube .

A solid sphere of mass 2 kg is resting inside a cube as shown in the figure. The cube is moving with a velocity v=(5t hati+2thatj)"m"//"s". Here t is the time in second. All surface are smooth. The sphere is at rest with respect to the cube. What is the total force exerted by the sphere on the cube? (Take g=10" m"//"s"^(2) )

A solid sphere of mass 2 kg is resting inside a cube as shown in fig. The cube is moving with a velocity vec(v)=(5t hat(i)+2t hat(j))ms^(-1) . Here t is time in seconds. All surface are smooth. The sphere is at rest with respect to the cube. What is the total force exerted by the sphere on the cube?

A solid sphere of mass 2 kg is resting inside a cube as shown in fig. The cube is moving with a velocity vec(v)=(5t hat(i)+2t hat(j))ms^(-1) . Here t is time in seconds. All surface are smooth. The sphere is at rest with respect to the cube. What is the total force exerted by the sphere on the cube?

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be

A soild block of mass 2 kg is resting inside a cube as shown in the figure .The cube is moving with a veocity v=5thati +2hatj m//s Here , t is is time in second the block is at rest with respect to the cube and cefficient of frision between the surface of ube and block is 0.6 then ,[take g=10m//s^(2) ]