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psi^2 ,( psi) the wave function respere...

` psi^2` ,( psi) the wave function resperesents the probability of finding electron . Its value depends :

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psi^ (2) determine the probability of finding the electron in particular region of sapce

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Assertion(A): psi indicates the amplitude of electron-wave psi^(2) denotes probability of finding an electron in the space around the nucleus

Probability of finding the electron psi^(2) of 's' orbital does not depend upon

Orbitals are the pictorial representationof Psi or Psi ^(2) Psi^(2) tell about the probability of finding electron. Which of the following graph is correct for 3p ?

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Orbitals are the pictorial representationof Psi or Psi ^(2) Psi^(2) tell about the probability of finding electron. A 2p_(x) orbital is shown by given diagram Correct regarding diagram is

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The Schrodinger wave equation for H-atom is nabla^(2) Psi = (8pi^(2)m)/(h^(2)) (E-V) Psi = 0 Where nabla^(2) = (del^(2))/(delx^(2)) +(del^(2))/(dely^(2)) +(del^(2))/(delz^(2)) E = Total energy and V=potential energy wave function Psi_(((r, theta,phi)))R_((r))Theta_((theta))Phi_((phi)) R is radial wave function which is function of ''r'' only, where r is the distance from nucleus. Theta and Phi are angular wave function. R^(2) is known as radial probability density and 4pir^(2)R^(2)dr is known as radial probability function i.e., the probability of finding the electron is spherical shell of thickness dr. Number of radial node =n -l - 1 Number of angular node = l For hydrogen atom, wave function for 1s and 2s-orbitals are: Psi_(1s) = sqrt((1)/(pia_(0)^(a)))e^(-z_(r)//a_(0)) Psi_(2s) = ((Z)/(2a_(0)))^(½) (1-(Zr)/(a_(0)))e^(-(Zr)/(a_(0))) The plot of radial probability function 4pir^(2)R^(2) aganist r will be: Answer the following questions: The following graph is plotted for ns-orbitals The value of 'n' will be: